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Q.

The plates in a parallel plates capacitor are separated by a distance d with air as the medium between the plates. In order to increase the capacity by 66% a dielectric slab of thickness 3d/5 is introduced between the plates. What is the dielectric constant of the dielectric slab?

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a

5

b

3

c

1.66

d

1.5

answer is B.

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Detailed Solution

Capacity in air C=ε0AdC′=ε0A(d−t)+tk t=3d5 Given C′=166100C100166=(d−t)+tKdOn putting valuesK = 3

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The plates in a parallel plates capacitor are separated by a distance d with air as the medium between the plates. In order to increase the capacity by 66% a dielectric slab of thickness 3d/5 is introduced between the plates. What is the dielectric constant of the dielectric slab?