Questions
The plates in a parallel plates capacitor are separated by a distance d with air as the medium between the plates. In order to increase the capacity by 66% a dielectric slab of thickness 3d/5 is introduced between the plates. What is the dielectric constant of the dielectric slab?
detailed solution
Correct option is B
Capacity in air C=ε0AdC′=ε0A(d−t)+tk t=3d5 Given C′=166100C100166=(d−t)+tKdOn putting valuesK = 3Talk to our academic expert!
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A parallel plate, air filled capacitor has capacitance C. When a dielectric material of dielectric constant 4 is filled so that half of the space between plates is occupied by it, then percentage increase in the capacitance is equal to
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