A platform is moving upwards with an acceleration of 5 ms-2. At the moment when its velocity is u = 3 ms-1, a ball is thrown from it with a speed of 30ms-1 w.r.t. platform at an angle of θ=30∘ with horizontal. The time taken by the ball to return to the platform is

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2 s

3 s

1 s

2.5 s

answer is A.

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Detailed Solution

0=usin⁡30∘t+12[−(a+g)]t2(a+g)t2=2usin⁡30∘tt=2usin⁡30∘a+g=2×30×12×15=2s

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