A player caught a cricket ball of mass I50 gm moving at the rate of 20 ms-1. If the catching process be completed in 0.1 s, the force of the blow exerted by the ball on the hands of the player is :

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0.3 N

30 N

300 N

3000 N

answer is B.

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Detailed Solution

F=ΔpΔt=150×10−3(20)0.1=30N

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