A player caught a cricket ball of mass l50 g moving at a rate of 20 m/s. If the catching process is completed in 0 . l second, the force of blow exerted by the ball on the hand of the player is equal to
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a
150 N
b
3 N
c
30 N
d
300N
answer is C.
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Detailed Solution
This problem can be solved by applying the theorem ofimpulse- momentum, i. e., |F×Δt|=∣ change in momentum ∣ F×0⋅1=pf−pi Hero pi=mvi=0⋅15×20=3 and pf=0 (ball stops after catching) ∴ F×0⋅1=|0−3|=3 F=30N