A player kicks a ball at a speed of 20 ms-1 so that its horizontal range is maximum. Another player 24 m away in the direction of kick starts running in the same direction at the same instant of hit. If he has to catch the ball just before it reaches the ground, he should run with a velocity equal to (Take g =10 ms-2)

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22ms−1

42ms−1

62ms−1

102ms−1

answer is B.

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Detailed Solution

Horizontal range, R=u2sin⁡2θgHorizontal range is maximum when angle of projection θ is 45oRmax=u2g=20210=40mTime of flight, T=2usin⁡45∘g=2×20×1210=22sThe player can catch the ball before reaching the ground if he covers a distance =40−24=16m in 22sThe velocity of that player must be =1622=42ms−1

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