A plumb bob is hung from the ceiling of a train compartment. The train moves on an inclined track of inclination $$30o$$ with horizontal. The acceleration of train up the plane is a $$=$$ $$g/2$$. The angle which the string supporting the bob makes with normal to the ceiling in equilibrium is

Question

Infinity Learn · Accepted Answer

Tsin⁡θ−mgsin⁡$$30$$∘$$=ma$$⇒ Tsin⁡θ$$=mgsin$$⁡$$30$$∘$$+mg/2$$   .....(i) Tcos⁡θ$$=mgcos$$⁡$$30$$∘    .....(ii)Dividing$$ Eqs. $$(i) by (ii), we gettan⁡θ$$=23$$

A plumb bob is hung from the ceiling of a train compartment. The train moves on an inclined track of inclination 30^owith horizontal. The acceleration of train up the plane is a = g/2. The angle which the string supporting the bob makes with normal to the ceiling in equilibrium is

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A plumb bob is hung from the ceiling of a train compartment. The train moves on an inclined track of inclination 30o with horizontal. The acceleration of train up the plane is a = g/2. The angle which the string supporting the bob makes with normal to the ceiling in equilibrium is

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A plumb bob is hung from the ceiling of a train compartment. The train moves on an inclined track of inclination 30^owith horizontal. The acceleration of train up the plane is a = g/2. The angle which the string supporting the bob makes with normal to the ceiling in equilibrium is