First slide

Radio activity

Question

Plutonium decays with a half-life of 24000 years. If the plutonium is stored for 72000 years, then the fraction of plutonium that remains is

Easy

A

$\frac{1}{2}$
B

$\frac{1}{3}$
C

$\frac{1}{4}$
D

$\frac{1}{8}$

Solution

$n = \frac{72000}{24000} = 3; Now \frac{N}{N_{0}} = {(\frac{1}{2})}^{n} = \frac{1}{8}$

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