First slide

Radio activity

Question

Plutonium decays with a half-life of 24,000 years. If plutonium is stored for 72,000 years, what fraction of it remains ?

Moderate

A

1/8
B

3/8
C

7/8
D

1/4

Solution

$\frac{M}{M_{0}} = \frac{1}{2^{t / T}} = \frac{1}{2^{(\frac{72000}{24000})}} = \frac{1}{2^{3}} = \frac{1}{8}$

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