Questions
In a p-n junction the depletion region is 400nm wide and electric field of 5 x 105 Vm-1 exists in it. The minimum energy of a conduction electron, which can diffuse from n-side to the p-side is
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a
4eV
b
5eV
c
0.4eV
d
0.2eV
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Correct option is D
W=Vq=Edq=5×105×400×10−9×1.6×10−19J=5×105×400×10−9×1.6×10−19J1.6×10−19eV=2000×10−4eV=0.2eVSimilar Questions
In dominant mechanisms for current due to charge carriers in forward and reverse biased p-n junctions are
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