In a pn junction diode, the thickness of depletion layer is 2 x 10-6m and barrier potential is 0.3v. The Intensity of the electric field at the junction is —

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0.6x10-6 v /m from n to p side

0.6x10-6 v /m from p to n side

1.5x105 v /m from n topside

1.5x105 v /m from p to n side

answer is C.

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Detailed Solution

E=vBd=0.32×10−6=1.5×105v/m Always from n to p side

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