Q.
In a pn junction diode, the thickness of depletion layer is 2 x 10-6m and barrier potential is 0.3v. The Intensity of the electric field at the junction is —
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a
0.6x10-6 v /m from n to p side
b
0.6x10-6 v /m from p to n side
c
1.5x105 v /m from n topside
d
1.5x105 v /m from p to n side
answer is C.
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Detailed Solution
E=vBd=0.32×10−6=1.5×105v/m Always from n to p side
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