A pnp transistor is used in CE mode in an amplifier circuit. A change of 40 μA in the base current brings a change of 2 mA in collector current and 0.04 V in base emitter voltage. The input resistance (Rin) in kΩ is

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Detailed Solution

Given : ΔIB=40μA, ΔIC=2mA , VBE=0.04V Input Resistance : Rin=VBEΔIB = 0.0440×10-6 = 1000Ω = 1 kΩ

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