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A point of application of a force $\vec{F} = 5 \hat{i} - 3 \hat{j} + 2 \hat{k}$ is moved from ${\vec{r}}_{1} = 2 \hat{i} + 7 \hat{j} + 4 \hat{k}$ top ${\vec{r}}_{2} = - 5 \hat{i} + 2 \hat{j} + 3 \hat{k}$ The work done is:

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-22units

22units

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11units

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Correct option is A

Displacement of the point is r→2−r→1=(−5i^+2j^+3k^)−(2i^+7j^+4k^) =−7i^−5j^−k^ Work done W=F→.(r→2−r→1) =(5i^−3j^+2k^).(−7i^−5j^−k^) =−35+15−2 =−22unit

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A point of application of a force F→=5i^−3j^+2k^ is moved from r→1=2i^+7j^+4k^ top r→2=−5i^+2j^+3k^ The work done is:

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A point of application of a force $\vec{F} = 5 \hat{i} - 3 \hat{j} + 2 \hat{k}$ is moved from ${\vec{r}}_{1} = 2 \hat{i} + 7 \hat{j} + 4 \hat{k}$ top ${\vec{r}}_{2} = - 5 \hat{i} + 2 \hat{j} + 3 \hat{k}$ The work done is: