First slide

Work done by Diff type of forces

Question

A point of application of a force F = 5 i -3 j+2 k is moved from r_i -2i+7 j+4k to r₂ =-5i+ 2j+3k. The work done is

Moderate

A

- 22 units
B

22 units
C

11 units
D

0 unit

Solution

Here displacement is given by
r₂ -r₁ = (-5i+2j+ 3k) -(2i+7j+4k)
= - 7 i - 5 j - k
Work done $= F \cdot (r_{2} - r_{1})$
$∴ W = (5 i - 3 j + 2 k) \cdot (- 7 i - 5 j - k)$
or W = -35+15-2=-22 units

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App