First slide

Gauss's Law

Question

A point charge 8.85 $μ C$ is placed at the centre of a cube. Then electric flux through one of the focus of the cube is

Moderate

A

$\frac{3}{4} \times 10^{6} V - m$
B

$\frac{1}{8} \times 10^{6} V - m$
C

$\frac{10^{6}}{6} V - m$
D

$\frac{1}{2} \times 10^{6} V - m$

Solution

Flux $ϕ$ through the entire surface of the cube $= \frac{Q}{\in_{0}}$
$∴$ Flux through one face $ϕ_{E} = \frac{ϕ}{6} = \frac{Q}{6 \in_{0}}$
$∴ ϕ_{E} = \frac{8.85 \times 10^{- 6}}{6 \times 8.85 \times 10^{- 12}} V - m = \frac{1}{6} \times 10^{6} V - m$

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