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Questions  

A point charge is placed at origin. Let EA,EB  and EC be the electric field at three points A (1,2,3), B (1,1,-1) and C (2,2,2) due to charge q1 then

a
EA→⊥EB→
b
EA→∥EC→
c
|EB→|=4|EC→|
d
|EB→|=8|EC→|

detailed solution

Correct option is M

EA→  is along OA→  and           EB→  is along OB→ OA→=i+2j+3k  and           OB→=i+j−k Since OA.→OB→=0                  EA→⊥EB→ Further |E→| α1r2                    |OC→| =2|OB→|                                               |EB→|=4|EC→|

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