A point charge is placed at origin. Let EA→,EB→ and EC→ be the electric field at three points A (1,2,3), B (1,1,-1) and C (2,2,2) due to charge q1 then

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EA→⊥EB→

EA→∥EC→

|EB→|=4|EC→|

|EB→|=8|EC→|

answer is M.

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Detailed Solution

EA→ is along OA→ and EB→ is along OB→ OA→=i+2j+3k and OB→=i+j−k Since OA.→OB→=0 EA→⊥EB→ Further |E→| α1r2 |OC→| =2|OB→| |EB→|=4|EC→|

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