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Q.

A point charge q=50μC is located in the x – y plane at the point of position vector r0→=2i^+3j.What is the electric field at the point of position vector r→=8i^−5j

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a

1200vm

b

4×10−2vm

c

900vm

d

4500vm

answer is D.

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Detailed Solution

r=(8−2)2+(−5−3)2=10E=9×109×50×10−6100=92×103=4500V/m
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