Download the app

Questions  

A point charge Q is fixed at origin. A dipole of dipole moment pi^  is placed at (a, 0). If the dipole is slowly turned such that its dipole moment becomes pj^  and it is then slowly moved to (a, a), the external work done on it will be

a
kpQa2(1−12)
b
kpQa2(1−122)
c
kpQa2(2−122)
d
kpQa2(1+122)

detailed solution

Correct option is B

The interaction potential energy of the system is kpcosθQr2  For the initial situation r=a, θ=180o, :Ui=kpcosθr2Q=−kpa2QFor the final situation : r=a2, θ=135o ,Uf=kpcosθr2Q=kp2a2(−12)QWext=Ut−Ui=kpa2(1−122)Q

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Two opposite and equal charges 4×108  coulomb when placed 2×102 cm away from a dipole. If this dipole is placed in an external electric field 4×108  newton / coulomb the value of maximum torque and the work done in rotating it through 1800  will be
 


phone icon
whats app icon