A point charge +Q is placed just outside an imaginary hemispherical surface of radius R as shown in the figure. Which of the following statements is/are correct?
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
The electric flux passing through the curved surface of the hemisphere is −Q2ε01−12
b
The component of the electric field normal to the flat surface is constant over the surface
c
Total flux through the curved and the flat surface is Qε0
d
The circumference of the flat surface is an equipotential
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
A) Flux passing through curved surface + Flux passing through flat surface = 0 ϕ=−Q4πε02π1−cosθ Put θ=45° =−Q2∈01−12 B) at x&r is variable: E E⊥=Esinα =kQr2Rr =KQRr3E⊥ is not constant over the surfaceC) Total flux through the curved and the flat surface is zero, because enclosed charge is zero.D) V=kQr=kQR2 . Circumference is equidistance from charge Q. Therefore it will be equipotential surface