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Q.

A point charge + q is placed at the origin as shown in fig. Work done in taking another point charge -Q from point A (0,a) to another point B (a,0) along the straight paths AB is

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a

zero

b

qQ4πε0×1a22a

c

−qQ4πε0×1a22a

d

qQ4πε0×1a2a2

answer is A.

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Detailed Solution

The potential energy of two charge systems is given by U=14πε0×q1q2rNow UA=14πε0×(+q)(−Q)a      =14πε0×(−qQ)aSimilarly, UB=14πε0×(−qQ)a∴ ΔU=UB−UA=0For conservative force W=−ΔU=0
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