Questions
A point charge + q is placed at the origin as shown in fig. Work done in taking another point charge -Q from point A (0,a) to another point B (a,0) along the straight paths AB is
detailed solution
Correct option is A
The potential energy of two charge systems is given by U=14πε0×q1q2rNow UA=14πε0×(+q)(−Q)a =14πε0×(−qQ)aSimilarly, UB=14πε0×(−qQ)a∴ ΔU=UB−UA=0For conservative force W=−ΔU=0Talk to our academic expert!
Similar Questions
Three point charges of equal value q are placed at the vertices of al equilateral triangle. The resulting lines of force should be sketch as in
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