First slide
Potential energy
Question

A point charge + q is placed at the origin as shown in fig. Work done in taking another point charge -Q from point A (0,a) to another point B (a,0) along the straight paths AB is

Moderate
Solution

The potential energy of two charge systems is given by U=14πε0×q1q2r
Now UA=14πε0×(+q)(Q)a
      =14πε0×(qQ)a
Similarly, UB=14πε0×(qQ)a
 ΔU=UBUA=0
For conservative force W=ΔU=0
 

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