First slide
Coulumbs law

The point charges 3μC and 4μC are placed at a separation of 7 m.  The medium between them is of two types as shown in figure, the electric force acting between them is


For finding air equivalent separation

We have 14πϵ0q1q2r2=14π0rq1q2r2      F=14π0q2q2r2

r=ϵrr       =1.73×104N

requivalent =(9)3+(16)4=25m

Therefore , F' =14πε0 q1q2requivalent2=9×109×3×4×10-12252 N =1.732×10-4 N

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App