The point charges 3μC and 4μC are placed at a separation of 7 m. The medium between them is of two types as shown in figure, the electric force acting between them is
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a
1.75×10−3N
b
1.73×10−4N
c
0.18×10−4N
d
0.18×10−3N
answer is B.
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Detailed Solution
For finding air equivalent separationWe have 14πϵ0q1q2r′2=14π∈0∈rq1q2r2 F′=14π∈0q2q2r′2⇒r′=ϵrr =1.73×10−4N∴requivalent =(9)3+(16)4=25mTherefore , F' =14πε0 q1q2requivalent2=9×109×3×4×10-12252 N =1.732×10-4 N