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Questions  

Point chargesq1=2μC q2=1μC are kept at Points x = 0 and = 6 respectively.  Electric poten-tial will be zero at the points

a
x=1 and x=5
b
x=2 and x=9
c
x=4 and x=12
d
x=−2 and x=2

detailed solution

Correct option is C

Let the potential be zero at P1 then ∴q1x=q2(6−x) 2×106x=1×106(6−x)⇒2x=16−x=12−2x=x  When potential is zero at P2, then kq1(6+x)=kq2x 2×10−6(6+x)=1×10−6x⇒26+x=1x⇒2x=6+x×=6 Distance from q1  is 12 cm.

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