Point charges q1=2μC and q2=-1μC are kept at points x = 0 and x = 6 respectively. Electric potential will be zero at the points:

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x = 1 and x = 5

x = 2 and x = 9

x = 4 and x = 12

x = -2 and x = 2

answer is C.

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Detailed Solution

For x1 kq1x1+kq26-x1=0⇒x1=4 cm For x2 kq2x2+kq2x2-6=0⇒x2=12 cm

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