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The point charges −2q,−2q and +q are put on the vertices of an equilateral triangle of side a. Find the work done by some external force in increasing the separation to 2a (in joules).

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Detailed Solution

W=Uf−Uiwhere Ui=14πε0a×[(−2q)(−2q)+(−2q)(q)+(q)(−2q)]=0 Also, Uf=0, So W=0.

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The point charges −2q,−2q and +q are put on the vertices of an equilateral triangle of side a. Find the work done by some external force in increasing the separation to 2a (in joules).