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Q.

A point dipole lies at the origin with its dipole moment along x-axis. A point charge when placed at (3a,0,0) and (a,0,0) experiences forces due to dipole with respectively magnitudesF1 andF2 .Then F2F1=

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a

27

b

127

c

8

d

19

answer is A.

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Detailed Solution

Along the axial line, electric field due to dipole is Eθ=0 andErα1r3 ⇒Fθ=0 andFrα1r3 ⇒F2F1=r13r23=(3a)3a3=27
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