The point from where a ball is projected is taken as the origin of the coordinate axes. The x and y components of its displacement are given by x = 6t and y = 8t - 5t2. What is the velocity of projection?
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a
6 ms-1
b
8 ms-1
c
10 ms-1
d
14 ms-1
answer is C.
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Detailed Solution
vx=dxdt=6 and vy=dydt=8−10t Putting t = 0 (Since we have to find initial velocity) yx=8−10×0=8 v=vx2+vy2=62+82=10ms−1