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Q.

The point from where a ball is projected is taken as the origin of the coordinate axes. The x and y components of its displacement are given by x = 6t and y = 8t - 5t2. What is the velocity of projection?

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a

6 ms-1

b

8 ms-1

c

10 ms-1

d

14 ms-1

answer is C.

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Detailed Solution

vx=dxdt=6 and vy=dydt=8−10t Putting t = 0 (Since we have to find initial velocity) yx=8−10×0=8 v=vx2+vy2=62+82=10ms−1
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