A point initially at rest moves along x-axis. Its acceleration varies with time as a=6t+5m/s2. If it starts from origin, the distance covered in 2s is:

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20 m

18 m

16 m

25 m

answer is B.

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Detailed Solution

a= 6t+5 v= ∫6t+5 dt = 3t2+5t s= ∫3t2+5t dt = t3 + 52t2 From 0 to 2 s, distance= 23+ 52×22 = 18

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