A point mass of 2kg is placed at the origin. At a distance of 6cm towards right another point mass of 1kg is placed. What is the total gravitational field intensity at a point distant 3cm to the right of the second mass?

E→P=E→2kg+E→1kgBoth the fields will be attractive and towards left. universal gravitation constant=G=6.67×10-11Nm2kg-2; mass=m; distance=r;Gravitational field strength  =Gmr2=E;  EP= E2kg+E1 kg    from principle of superposition E2kg=G×29×10−22=0.165×10−7N/kgE1 kg =G×13×10−22=0.741×10−7N/kgEP= E2kg+E1 kg    from principle of superpositionEP=0.165×10−7+0.741×10−7N/kgEP=0.906×10−7N/kg