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Q.

A point mass MA is connected to a point mass MB by a massless rod of length l as shown in the figure. It is observed that the ratio of the moment of inertia of the system about the two axes BB and AA, which is parallel to each other and perpendicular to the rod is IBBIAA=3 . The distance of the centre of mass of the system from the mass MA is

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a

(3/4) l

b

(2/3) l

c

(1/2) l

d

(1/4) l

answer is D.

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Detailed Solution

IBB=MAl2     IAA=MBl2  given= IBBIAA= 3    MAMB=3 center of mass from MA=MBMB+MAl= MB4 MBl  =14 l
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