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Q.

A point mass oscillates along the x-axis according to the law x=x0cos ωt-π4. If the acceleration of the particle is written as a=A cos ωt+δ,then :

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a

A=xoω2,δ=3π4

b

A=xo,δ=-π4

c

A=xoω2,δ=π4

d

A=xoω2,δ=-π4

answer is A.

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Detailed Solution

Acceleration, a=d2xdt2=-x0ω2cosωt-π4                =x0ω2cos ωt-π4+π                 =x0ω2cosωt+3π4 ⇒         A=x0ω2and δ=3π4
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