Questions
A point mass starts moving in a straight line with constant acceleration. After time the acceleration changes its sign, remaining the same in magnitude. Determine the time from the beginning of motion in which the point mass returns to the initial position.
detailed solution
Correct option is B
If we start time calculations from point $P$ and apply the equation,s=ut+12at2 -12at02=+at0t+12(-a)t2 Solving we get, t=(2+1)t0 =2.414t0 Total time, T=t+t0 =(3.414)t0Talk to our academic expert!
Similar Questions
A ball is dropped from a height of 49 m, the wind blows horizontally and imparts a constant acceleration of 4.90 ms-2 to the ball. Choose the correct statement(s).
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
