A point moves in a straight line so that its displacement 'y'm at time 't'sec is given by y2=1+t2 . Its acceleration in m/s2 at time 't'sec

Given that y2=1+t2y=1+t21/2 Velocity V=dydt=121+t2−12⋅2t=t1+t2−12∴ acceleration a=dvdt=t−121+t2−3/2×2t+1+t2−12×1=−t21+t2−3/2+1+t2−1/2But from given data  1+t2=y2∴ acceleration  a=−t2y2−3/2+y2−1/2                           a=−t2y3+1y