A point moves such that its displacement as a function of time is given by x3=t3+1. Its acceleration as a function of time t will be

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2x5

2tx5

2tx4

2t2x5

answer is B.

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Detailed Solution

x3=t3+1⇒3x2dxdt=3t2⇒dxdt=t2x2 …(i)d2xdt2=2tx2−2xdxdtt2x4=1x42tx2−2xt2t2x2=2tx2x41−t3x3=2tx2x41−x3−1x3=2tx5

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