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Questions  

A point moves such that its displacement as a function of time is given by x3=t3+1. Its acceleration as a function of time t will be

a
2x5
b
2tx5
c
2tx4
d
2t2x5

detailed solution

Correct option is B

x3=t3+1⇒3x2dxdt=3t2⇒dxdt=t2x2                …(i)d2xdt2=2tx2−2xdxdtt2x4=1x42tx2−2xt2t2x2=2tx2x41−t3x3=2tx2x41−x3−1x3=2tx5

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