A point moves with uniform acceleration and v1, v2 and v3 denote the average velocities in the three successive intervals of time t1, t2 and t3. Which of the following relations is correct?
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a
(v1 - v2) : (v2 - v3)= (t1 - t2) : (t2 + t3)
b
(v1 - v2) : (v2 - v3)= (t1 + t2) : (t2 + t3)
c
(v1 - v2) : (v2 - v3)= (t1 - t2) : (t1 - t3)
d
(v1 - v2) : (v2 - v3)= (t1 - t2) : (t2 - t3)
answer is B.
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Detailed Solution
Average velocity in uniformly accelerated motion is given by vav=st=ut+12at2t=u+12atNow, v1=u+12at1, v2=u+at1+12at2and v3=u+at1+t2+12at3∴ v1-v2:v2-v3=t1+t2:t2+t3