A point moves with uniform acceleration and v1, v2, and v3 denote the average velocities in the three successive intervals of time t1, t2 and t3. Which of the following relations is correct ?
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
(v1 - v2) : (v2-v3) = (t1 - t2) : (t2 + t3)
b
(v1 - v2) : (v2 - v3) = (t1 + t2) : (t2+ t3)
c
(v1-v2) : (v2-v3 ) = (t1 - t2) : (t1 - t3)
d
(v1 - v2): (v2-v3) = (t1-t2) : ( t2-t3)
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Suppose u be the initial velocity. Velocity after time t1 :v11=u+ at Velocity after time t1+t2 : v22=u+at1+t2 Velocity after time t1+t2+t3:v33=u+at1+t2+t3 Now, v1=u+v112=u+u+at12=u+12at1 v2=v11+v222=u+at1+12at2 v3=v22+v332=u+at1+at2+12at3 So v1-v2=-12at1+t2 v2-v3=-12at2+t3 v1-v2:(v2-v3)=t1+t2:t2+t3