The point A moves with a uniform speed along the circumference of a circle of radius 0.36 m and covers 300 in 0.1s. The perpendicular projection ‘P’ from ‘A’ on the diameter MN represents the simple harmonic motion of ‘P’. The restoration force per unit mass when P touches M will be:

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0.49 N

9.87 N

50 N

100 N

answer is B.

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Detailed Solution

Amplitude = radius of circle=0.36mAngular frequency = Angular speed=θt=π60.1=π0.6sWhen P touches M, Fmax=mamax⇒Fmax=mω2A⇒Fmaxm=π0.62×0.36=9.87N

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