The point A moves with a uniform speed along the circumference of a circle of radius $$0.36$$ m and covers $$300$$ in $$0.1s$$. The perpendicular projection ‘P’ from ‘A’ on the diameter MN represents the simple harmonic motion of ‘P’. The restoration force per unit mass when P touches M will be:

Question

The point A moves with a uniform speed along the circumference of a circle of radius $$0.36$$ m and covers $$300$$ in $$0.1s$$. The perpendicular projection ‘P’ from ‘A’ on the diameter MN represents the simple harmonic motion of ‘P’. The restoration force per unit mass when P touches M will be:

Infinity Learn · Accepted Answer

Amplitude $$=$$ radius of $$circle=0.36mAngular$$ frequency $$=$$ Angular $$speed=$$θ$$t=$$π$$60.1=$$π$$0.6sWhen$$ P touches M, $$Fmax=mamax$$⇒$$Fmax=m$$ω$$2A$$⇒$$Fmaxm=$$π$$0.62$$×$$0.36=9.87N$$

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The point A moves with a uniform speed along the circumference of a circle of radius 0.36 m and covers 300 in 0.1s. The perpendicular projection ‘P’ from ‘A’ on the diameter MN represents the simple harmonic motion of ‘P’. The restoration force per unit mass when P touches M will be:

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