A point object at 15cm from a concave mirror of radius of curvature 20cm is made it oscillate along the principal axis with amplitude 2mm. The amplitude of its image will be
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a
2 mm
b
4 mm
c
16 mm
d
8 mm
answer is D.
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Detailed Solution
according to mirror formula115+1v=220=110 solving v=30 then magnification m= vu=3015=2 this is transverse magnification longitudinal magnification dvdu=-v2u2= m2 =4 so amplitude of image oscillation is 2x4=8