A point particle of mass $$0.1$$ kg is executing SHM of amplitude of $$0.1$$ m. When the particle passes through the mean position, its kinetic energy is $$18$$×$$10-3$$ J. The equation of motion of this particle when the initial phase of oscillation is $$45$$° can be given by $$-$$

Question

A point particle of mass $$0.1$$ kg is executing SHM of amplitude of $$0.1$$ m. When the particle passes through the mean position, its kinetic energy is $$18$$×$$10-3$$ J. The equation of motion of this particle when the initial phase of oscillation is $$45$$° can be given by $$-$$

Infinity Learn · Accepted Answer

Given : $$A=0.1$$ m,  $$m=0.1$$ kg, $$KEmax=18$$×$$10$$−$$3$$ J, ϕ$$=$$π$$4$$​$$KEmax=12m$$ω$$2A2$$⇒ω$$=2KEmaxmA2=6rad/s$$​∴ Equation of SHM is  $$y=0.1sin(6t+$$π$$4)$$

A point particle of mass 0.1 kg is executing SHM of amplitude of 0.1 m. When the particle passes through the mean position, its kinetic energy is $18 \times 10^{- 3} J$ . The equation of motion of this particle when the initial phase of oscillation is $45 °$ can be given by -

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A point particle of mass 0.1 kg is executing SHM of amplitude of 0.1 m. When the particle passes through the mean position, its kinetic energy is 18×10-3 J. The equation of motion of this particle when the initial phase of oscillation is 45° can be given by -

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Ready to Test Your Skills?

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A point particle of mass 0.1 kg is executing SHM of amplitude of 0.1 m. When the particle passes through the mean position, its kinetic energy is $18 \times 10^{- 3} J$ . The equation of motion of this particle when the initial phase of oscillation is $45 °$ can be given by -