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A point source of electromagnetic radiation has an average power output of 15 W.  The maximum  value of electric field at a distance of 3m from this source in Vm1  is 

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a
10
b
20
c
15
d
5

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detailed solution

Correct option is A

I=P4πr2=12∈0E02C ⇒E0=P2πr2∈0c12 ⇒E0=152π×9×3×1084π×9×10912 ⇒E0=10212=10Vm


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In an electromagnetic wave, the electric and magnetising fields are 100Vm-1 and 0.265Am-1. The maximum energy flow is 


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