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A point source of light B is placed at a distance L in front of the centre of a mirror of width d hung vertically on a wall. A man walks in front of the minor along a line parallel to the mirror at a distance 2 L from it as shown. The greatest distance over which he can see the image of the light source in the mirror is

a
d/2
b
d
c
2d
d
3d

detailed solution

Correct option is D

According to the following ray diagram HI = AB = dand   DS=CD=d2∵Ah=2AD⇒GH=2CD=2d2=dsimilarly  IJ=d   so  GJ=GH+HI+IJ=d+d+d=3d

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