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A point source of light S, placed at a distance 60cm in front of the centre of a plane mirror of width 50cm, hangs vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror a distance 1.2m from it (see in the figure). The distance between the extreme points where he can see the image of the light source in the mirror is ____________cm.

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answer is 150.

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Detailed Solution

Using properties of similar triangles, 2560=tan⁡θ=y1.2⇒y=0.5m=50cm Thus, length of field of view =y+50+y=150cm

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A point source of light S, placed at a distance 60cm in front of the centre of a plane mirror of width 50cm, hangs vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror a distance 1.2m from it (see in the figure). The distance between the extreme points where he can see the image of the light source in the mirror is ____________cm.