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Q.

A point source of power 50π watts is producing sound waves of frequency 1875 Hz. The velocity of sound is 330 m/s, atmospheric pressure is 1.0 × 105 Pa, density of air is 40099πkgm-3. Then the displacement amplitude at r = 330  m from the point source is

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a

0.5 μm

b

0.2 μm

c

1 μm

d

2 μm

answer is C.

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Detailed Solution

I=P4πr2=2πρvf2A2   ⇒   A=I2πfrP2πρvHence A=12π×1875×330×(50π)2π×40099π×330 m = 1.13×10-6 m = 1.13 μm.
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A point source of power 50π watts is producing sound waves of frequency 1875 Hz. The velocity of sound is 330 m/s, atmospheric pressure is 1.0 × 105 Pa, density of air is 40099πkgm-3. Then the displacement amplitude at r = 330  m from the point source is