A point source S is placed at the bottom of different layers as shown in Fig. the refractive index of bottom most layer is $μ_{o}$ . The refractive index of any other upper layer is
$μ (n) = μ_{o} - \frac{μ_{o}}{4 n - 18} where n = 1, 2, . ..$ A ray of light starts form the source S as shown. Total internal reflection takes place at the upper surface of a layer having ir equal to

Question

A point source S is placed at the bottom of different layers as shown in Fig. the refractive index of bottom most layer is $μ_{o}$ . The refractive index of any other upper layer is

$μ (n) = μ_{o} - \frac{μ_{o}}{4 n - 18} where n = 1, 2, . ..$ A ray of light starts form the source S as shown. Total internal reflection takes place at the upper surface of a layer having ir equal to

Infinity Learn · Accepted Answer

When     $$n=1$$μ$$1=$$μo−μ$$o4$$×$$1$$−$$18$$⇒μ$$1$$>μoWhen  $$n=2$$,μ$$2=$$μo−μ$$o4$$×$$2$$−$$18$$⇒μ$$2$$>μoWhen  $$n=4$$,μ$$4=$$μo−μ$$o4$$×$$4$$−$$18$$⇒μ$$4$$>μoWhen  $$n=5$$,μ$$5=$$μo−μ$$o5$$×$$4$$−$$18$$⇒μ$$5$$<μoClearly, the total internal reflection shall take place at the top of a layer having n $$=$$ $$4$$.

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