First slide

Elastic Modulie

Question

The Poisson's ratio of a material is 0.5. If a force is applied to a wire of this material, there is a decrease in the cross-sectional area by 4%. The percentage increase in the
length is:

Easy

A

1%
B

2%
C

2.5%
D

4%

Solution

$\frac{∆ A}{A} = 2 \frac{∆ r}{r} \Rightarrow \frac{∆ r}{r} = \frac{4}{2} = 2 % \frac{∆ l}{l} = \frac{∆ r / r}{σ} = \frac{2}{0.5} = 4 %$

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