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The Poisson’s ratio of material is 0.4. If a force is applied to a wire of this material, there is a decrease of cross-sectional area by 2%. The percentage increase in its length is 

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a
3%
b
2.5%
c
1%
d
0.5%

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detailed solution

Correct option is B

As, A=πD2/4 ΔAA=2ΔDD or  ΔDD=12ΔAA=12×2=1% Now     σ=ΔD/DΔl/l or   Δll=ΔD/Dσ=10.4=2.5%


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