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Q.

The Poisson’s ratio of material is 0.4. If a force is applied to a wire of this material, there is a decrease of cross-sectional area by 2%. The percentage increase in its length is

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a

3%

b

2.5%

c

1%

d

0.5%

answer is B.

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Detailed Solution

As, A=πD2/4 ΔAA=2ΔDD or  ΔDD=12ΔAA=12×2=1% Now     σ=ΔD/DΔl/l or   Δll=ΔD/Dσ=10.4=2.5%
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