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The pole strength of a bar magnet is 48 Am and the distance between its poles is 25 cm. The moment of the couple by which it can be placed at an angle of 30o with the uniform magnetic intensity of flux density 0.15 N/A-m will be

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a
12 Nm
b
18 Nm
c
0.9 Nm
d
None of these

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detailed solution

Correct option is C

τ= MBsinθ= 48 x 25 x l0-2 x 0.15 x 12= 0.9 N-m

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