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The pole strength of a bar magnet is 48 Am and the distance between its poles is 25 cm. The moment of the couple by which it can be placed at an angle of with the uniform magnetic intensity of flux density 0.15 N/A-m will be
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Correct option is C
τ= MBsinθ= 48 x 25 x l0-2 x 0.15 x 12= 0.9 N-m
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