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The pole strength of a bar magnet is 48 Am and the distance between its poles is 25cm. The moment of the couple by which it can be placed at an angle of $30^{0}$ with the uniform magnetic field of flux density 0.15 N/Am will be.

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detailed solution

Correct option is C

Moment of the couple means torque and flux density means magnetic field.∴Torque, Γ=MBSinθ=m l BSinθ [m=pole strength]=48 x 0.25 x 0.15 x 12= 0.9 Nm

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The pole strength of a bar magnet is 48 Am and the distance between its poles is 25cm. The moment of the couple by which it can be placed at an angle of 300 with the uniform magnetic field of flux density 0.15 N/Am will be.

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Ready to Test Your Skills?

free study material

The pole strength of a bar magnet is 48 Am and the distance between its poles is 25cm. The moment of the couple by which it can be placed at an angle of $30^{0}$ with the uniform magnetic field of flux density 0.15 N/Am will be.