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Questions  

Position of a body with acceleration ‘a’ is given by  x=Kamtn, here t is time. Find values of m and n.

a
m = 1,  n = 1
b
m = 1,  n = 2
c
m = 2,  n = 1
d
m = 2, n = 2

detailed solution

Correct option is B

As x = Kam×tnM0L1T0 = LT−2mTn  =  LmT2m+n∴  m = 1 and  −2m+n = 0  ⇒ n = 2.

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