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Q.

Position of a body with acceleration ‘a’ is given by  x= Kamtn, here t is time. Find values of m and n.

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a

m = 1,  n = 1

b

m = 1,  n = 2

c

m = 2,  n = 1

d

m = 2, n = 2

answer is B.

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Detailed Solution

As x = Kam×tnM0L1T0 = LT−2mTn  =  LmT2m+n∴  m = 1 and  −2m+n = 0  ⇒ n = 2.
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