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A position dependent force, $F = 7 - 2 x + 3 x^{2}$ newton acts on a small body of mass 2 kg and displaces it from $x = 0 to x = 5 m$ The work done in Joule is

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Correct option is D

W=∫05 F×dx =∫05 7−2x+3x2dx =[7x]05−2x2205+3x3305 =35−25+125−135 joule

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A position dependent force, F=7−2x+3x2newton acts on a small body of mass 2 kg and displaces it from x=0 to x=5m The work done in Joule is

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A position dependent force, $F = 7 - 2 x + 3 x^{2}$ newton acts on a small body of mass 2 kg and displaces it from $x = 0 to x = 5 m$ The work done in Joule is