A position dependent force F=7−2x+3x2 newton acts on a small body of mass 2 kg and displaces it from x=0 to x=5 m. The work done in joules is
W=∫05Fdx=∫05(7−2x+3x2) dx=[7x−x2+x3]05
= 35 – 25 + 125 = 135 J