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In position A kinetic energy of a particle is 60 J and potential energy is -20 J. In position B, kinetic energy is 100 J and potential energy is 40 J. Then, in moving the particle from A to B

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Detailed Solution

Work done by conservative forces =Ui−Uf=−20−40=−60 JWork done by external forces=Ef−Ei=140−40=100 JWork done by all the forces=Kf−Ki=100−60=40 J
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In position A kinetic energy of a particle is 60 J and potential energy is -20 J. In position B, kinetic energy is 100 J and potential energy is 40 J. Then, in moving the particle from A to B