First slide

Work done by Diff type of forces

Question

In position A kinetic energy of a particle is 60 J and potential energy is -20 J. In position B, kinetic energy is 100 J and potential energy is 40 J. Then, in moving the particle from A to B

Moderate

Solution

Work done by conservative forces $= U_{i} - U_{f} = - 20 - 40 = - 60 J$
Work done by external forces $= E_{f} - E_{i} = 140 - 40 = 100 J$
Work done by all the forces $= K_{f} - K_{i} = 100 - 60 = 40 J$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App